Asked by Anonymous
What is the seperation energy ineV for Be3+ in the first excited state in eV?
Answers
Answered by
DrBob222
1/wavelength = RZ^2(1/1^2 - 1/infinity)
R is Rydberg constant. You can look that up in (in meters)
The term of 1/infinity will be zero.
This will give you wavelength and you can convert to energy with E = hc/wavelength.
Z is the atomic number of Be
R is Rydberg constant. You can look that up in (in meters)
The term of 1/infinity will be zero.
This will give you wavelength and you can convert to energy with E = hc/wavelength.
Z is the atomic number of Be
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