Question
r=4/(-2-6sinϴ)
1. What is the eccentricity of the function?
2. What is the distance between the pole and the directrix?
1. A. 2
B. -2
C. 3
D. -3
2. A. 2
B. 2/3
C. 3
D. 6
1. What is the eccentricity of the function?
2. What is the distance between the pole and the directrix?
1. A. 2
B. -2
C. 3
D. -3
2. A. 2
B. 2/3
C. 3
D. 6
Answers
Steve
So, I guess you did not read the web page I suggested ...
r = ed/(1+e sin?)
r=4/(-2-6sin?)
r = -2/(1+3sin?)
so, e=3 and d=2/3
in x-y coordinates, that is
(y-3/4)^2 - x^2/8 = 1/16
http://www.wolframalpha.com/input/?i=hyperbola+(y-3%2F4)%5E2+-+x%5E2%2F8+%3D+1%2F16
You can see that with a focus at (0,0), vertex at (0,1/2) and eccentricity of 3 it agrees with the information from the polar form.
r = ed/(1+e sin?)
r=4/(-2-6sin?)
r = -2/(1+3sin?)
so, e=3 and d=2/3
in x-y coordinates, that is
(y-3/4)^2 - x^2/8 = 1/16
http://www.wolframalpha.com/input/?i=hyperbola+(y-3%2F4)%5E2+-+x%5E2%2F8+%3D+1%2F16
You can see that with a focus at (0,0), vertex at (0,1/2) and eccentricity of 3 it agrees with the information from the polar form.