15 Show that 4x+3/2x + 3/5 can be written in the form ax+b/cx where a, b and c are integers..

Answer 1

To write 4x + 3/2x + 3/5 in the form ax + b/cx, we need to find the value of a, b, and c in such a way that the equation is equivalent.

First, let's find a common denominator for the fractions. The least common multiple of 2 and 5 is 10, so we can rewrite the equation as:

(4x(5/5) + 3/2x(5/5) + 3/5) = (20x + 15/10x + 6/10)

Now, we can simplify this expression:

20x + 15/10x + 6/10
= (20x + 15) / (10x) + 6/10

To compare this expression to the desired form ax + b/cx, we need to separate the fraction (20x + 15) / (10x) + 6/10 into two fractions with denominators of 10x:

(20x + 15) / (10x) + 6/10
= (20x + 15) / (10x) + (6x) / (10x)
= (20x + 15 + 6x) / (10x)
= (26x + 15) / (10x)

Now we have an expression in the form ax + b/cx, where a = 26, b = 15, and c = 10.

So, 4x + 3/2x + 3/5 can be written in the form 26x + 15/10x.