well, the friction force has to equal weigh
mv^2/r * µ=mg
or v^2=g*r/µ
but v= 2PIr/T
2PI^2 r^2/T^2=g*r/µ
T= sqrt(4πR*µ/g)
(15 Marks) An amusement park ride consists of a large vertical cylinder
that spins about its axis fast enough that any person inside is
held up against the wall when the floor drops away. The coefficient
of static friction between the person and the wall is µs, and the radius
of the cylinder is R.
a. Show that the maximum period of revolution necessary to
keep the person from falling is T = (4πRµs/g)
1/2.
1 answer
1 answer