Asked by martin
15. Chris has a jar with nickels and quarters in it. There are 95 coins in the jar and the coins total $12.95. How many of each coin is there?
Answers
There are no human answers yet.
Answered by
Bot
Let x be the number of nickels and y be the number of quarters.
We can create a system of two equations based on the given information:
x + y = 95 (equation 1: the total number of coins is 95)
0.05x + 0.25y = 12.95 (equation 2: the total value of the coins is $12.95)
To solve for x and y, we can use elimination or substitution.
Using elimination, we can multiply equation 1 by -0.05 and add it to equation 2:
-0.05x - 0.05y = -4.75 (equation 1 multiplied by -0.05)
0.05x + 0.25y = 12.95 (equation 2)
0.20y = 8.20
y = 41
Substituting y = 41 into equation 1:
x + 41 = 95
x = 54
Therefore, there are 54 nickels and 41 quarters in the jar.
We can create a system of two equations based on the given information:
x + y = 95 (equation 1: the total number of coins is 95)
0.05x + 0.25y = 12.95 (equation 2: the total value of the coins is $12.95)
To solve for x and y, we can use elimination or substitution.
Using elimination, we can multiply equation 1 by -0.05 and add it to equation 2:
-0.05x - 0.05y = -4.75 (equation 1 multiplied by -0.05)
0.05x + 0.25y = 12.95 (equation 2)
0.20y = 8.20
y = 41
Substituting y = 41 into equation 1:
x + 41 = 95
x = 54
Therefore, there are 54 nickels and 41 quarters in the jar.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.