To balance the given chemical equations, we will adjust the coefficients before each compound to ensure that the number of atoms of each element is the same on both sides of the equation.
15. Balance the following chemical equation: \[ _____ \text{Mg} + _____ \text{O}_2 \rightarrow _____ \text{MgO} \]
Balancing:
- Start with magnesium (Mg): Each MgO has one Mg, so whatever the number of Mg on the left should be the same on the right.
- Oxygen (O): Since O2 has 2 oxygen atoms, and each MgO has 1, we'll need 2 MgO for every O2 to balance the oxygen.
To balance:
- Let Mg = 2
- O2 = 1
- MgO = 2
The balanced equation is: \[ 2 \text{Mg} + 1 \text{O}_2 \rightarrow 2 \text{MgO} \]
16. Balance the following chemical equation: \[ _____ \text{Ti}_3\text{N} + _____ \text{MgO} \rightarrow _____ \text{Mg}_3\text{N}_2 + _____ \text{Ti}_2\text{O} \]
Balancing:
- For Ti: There are 3 titanium atoms in Ti3N and 2 in Ti2O, so we need 3/2 Ti2O to balance Ti.
- For N: There is 1 nitrogen in Ti3N, and we produce 2 nitrogen atoms from 1 Mg3N2. Thus, we need 2 Ti3N to produce the right amount of Mg3N2.
- For Mg: Since we need a total of 3 magnesium atoms for Mg3N2, we will balance it through coefficients.
Adjusting the coefficients, we find:
- \( 2 \text{Ti}_3\text{N} + 3 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 2 \text{Ti}_2\text{O} \)
This gives us:
The balanced equation is: \[ 2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O} \]
Final balanced equations:
15. \( 2 \text{Mg} + 1 \text{O}_2 \rightarrow 2 \text{MgO} \)
16. \( 2 \text{Ti}_3\text{N} + 6 \text{MgO} \rightarrow 3 \text{Mg}_3\text{N}_2 + 4 \text{Ti}_2\text{O} \)
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