To determine reasonable scales for the vertical axis (cost) of the function \( t(d) = 50d + 200 \), we can analyze the function based on the values of \( d \) (the number of days).
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Minimum Cost: When \( d = 0 \): \[ t(0) = 50(0) + 200 = 200 \] The minimum cost is $200.
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For various values of \( d \):
- \( d = 1 \): \( t(1) = 50(1) + 200 = 250 \)
- \( d = 2 \): \( t(2) = 50(2) + 200 = 300 \)
- \( d = 3 \): \( t(3) = 50(3) + 200 = 350 \)
- \( d = 4 \): \( t(4) = 50(4) + 200 = 400 \)
- And so on...
Given the range of values (starting from $200 and increasing), the reasonable scales for the vertical axis (the cost) would be those that make sense within this context and that can fit above $200.
Let's evaluate the options:
- $1: Not reasonable, since the minimum cost is $200.
- $5: Not reasonable, since the minimum cost is $200.
- $25: Not reasonable, since the minimum cost is $200.
- $50: Not reasonable, since the minimum cost is $200.
- $100: Not reasonable, since the minimum cost is $200.
- $400: Reasonable, as it falls within the expected range of costs (e.g., for 4 days).
Therefore, the only reasonable scale for the vertical axis is:
- $400