15.0g of potassium trioxochlorate(v) was crushed and heated with about 0.1g of manganese(iv)oxide Calculate the mass of KCl that will be produced assuming the reaction was complete

1 answer

Your name for KClO3 is not correct and is not an accepted name by IUPAC. Manganese(IV) oxide is a correct name for MnO2.That iv should be capitalized.
2KClO3 ==> 2KCl + 3O2
mols KClO3 = grams/molar mass = 15.0/molarmass KClO3 = ?
Convert to mols KCl produced. That is mols KClO3 x (2 mols KCl/2 mols KClO3) = ?

Then grams KCl = mols KCl x molar mass KCl = ?
Post your work if you get stuck.