Asked by Sade

Given: 5cos6Θ

What is the shape of the function?

A. Limacon
B. Rose
C. Lemniscate
D. Circle
Answered by Steve
if n is even,

r = a cos(n?) is a rosette with 2n leaves.

Think about it. cos(n?) goes from 1 to 0 every time n? grows by pi/2. So, in [0,2pi], 6? goes in and out 12 times.

You can always verify your work online, as at

http://www.wolframalpha.com/input/?i=r%3D5cos(6%CE%B8)

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