Asked by Anna Alkine
Find the number of units that produces a
maximum revenue given by R = 290x−0.2x
2, where R is the total revenue in dollars and x is the number of units sold.
Answer in units of units.
maximum revenue given by R = 290x−0.2x
2, where R is the total revenue in dollars and x is the number of units sold.
Answer in units of units.
Answers
Answered by
Bosnian
A quadratic equation have the standrad form:
a x ^ 2 + b x + c
R = 290 x − 0.2 x ^ 2 is quadratic equation:
R = − 0.2 x ^ 2 + 290 x + 0
The vertex of a quadratic parabola is the highest or lowest point, the maximum or minimum.
When a < 0 a quadratic parabola has a maximum.
In this equation : a = - 0.2 , b = 290 , c = 0
x coordinate of vertex:
x = - b / 2 a
In this case:
x = - 290 / [ 2 * ( - 0.2 ) ]
x = - 290 / - 0.4
x = 725
Replace this value in equation:
R = 290 x − 0.2 x ^ 2
Rmax = 290 * 725 - 0.2 * 725 ^ 2
Rmax = 210,250 - 0.2 * 525,625
Rmax = 210,250 - 105,125
Rmax = 105,125
725 units sold
Rmax = $105,125
a x ^ 2 + b x + c
R = 290 x − 0.2 x ^ 2 is quadratic equation:
R = − 0.2 x ^ 2 + 290 x + 0
The vertex of a quadratic parabola is the highest or lowest point, the maximum or minimum.
When a < 0 a quadratic parabola has a maximum.
In this equation : a = - 0.2 , b = 290 , c = 0
x coordinate of vertex:
x = - b / 2 a
In this case:
x = - 290 / [ 2 * ( - 0.2 ) ]
x = - 290 / - 0.4
x = 725
Replace this value in equation:
R = 290 x − 0.2 x ^ 2
Rmax = 290 * 725 - 0.2 * 725 ^ 2
Rmax = 210,250 - 0.2 * 525,625
Rmax = 210,250 - 105,125
Rmax = 105,125
725 units sold
Rmax = $105,125
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