How would I draw the structure for (3e,5z)-6-bromo-3-fluoro-3,5-nonadiene? I drew out the main chain of 9 C's, fluoride on 3, double bond between 3 and 4, double bond between 5 and 6, bromide extending out from 6. I understanding E is Trans (priorities opposite) and Z is cis (priorities same direction) but this is particularly confusing. Please help!!
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