Find the area of the region enclosed between y=4sin(x) and y=2cos(x) from x=0 to x=0.7pi.

Hint: Notice that this region consists of two parts.

1 answer

let f(x) = 4sinx, g(x) = 2cosx.

the graphs cross at u=arctan(1/2), so the area is

∫[0,u] (g-f) dx + ∫[u,.7π] (f-g) dx