Asked by Jamie
Find the area of the region enclosed between y=4sin(x) and y=2cos(x) from x=0 to x=0.7pi.
Hint: Notice that this region consists of two parts.
Hint: Notice that this region consists of two parts.
Answers
Answered by
Steve
let f(x) = 4sinx, g(x) = 2cosx.
the graphs cross at u=arctan(1/2), so the area is
∫[0,u] (g-f) dx + ∫[u,.7π] (f-g) dx
the graphs cross at u=arctan(1/2), so the area is
∫[0,u] (g-f) dx + ∫[u,.7π] (f-g) dx
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