Asked by Raj
If 0.01% of electrons are removed from 18 gm water, then calculate the charge produced
in the water.
in the water.
Answers
Answered by
bobpursley
.01 mole= .01*Avagnumber*e
= .01*6.02E23*1.6E-19 coulomb
= about.1E4 coulomb in my head
= .01*6.02E23*1.6E-19 coulomb
= about.1E4 coulomb in my head
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