Asked by Raven-Sierra
Answer the questions about the following reaction.
4Al(s) + 3O2(g) 2Al2O3 (s)
How many molecules of O2 are used in the reaction?
How many oxygen atoms are required?
How many moles of Al2O3 are formed?
What is the mole ratio of Al to O2?
4Al(s) + 3O2(g) 2Al2O3 (s)
How many molecules of O2 are used in the reaction?
How many oxygen atoms are required?
How many moles of Al2O3 are formed?
What is the mole ratio of Al to O2?
Answers
Answered by
bobpursley
for the first three, one wonders. How much (in grams, moles, or else) was invovled in the reaction? 1gram, or 200 tons?
mole ratio of Al to O2: 4::3
mole ratio of Al to O2: 4::3
Answered by
Sav
1. 3 mols of O2 * 6.022*10^23
1mol
so 3*6.022*10^23= 1.8066*10^24
molecules of O2
2. 3O2 2atoms*3moles=6
2Al2O3 3atoms*2moles=6
6+6= 12 total O atoms
3. 4 moles of Al for every 3 moles of
O2= 4:3 mole to mole ratio
1mol
so 3*6.022*10^23= 1.8066*10^24
molecules of O2
2. 3O2 2atoms*3moles=6
2Al2O3 3atoms*2moles=6
6+6= 12 total O atoms
3. 4 moles of Al for every 3 moles of
O2= 4:3 mole to mole ratio
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