centripetal acc = v^2 / r
... v is the tangential velocity
16.7 = v^2 / 6.41E6
v / r = angular velocity (in radians)
An airplane is flying above the Earth's surface at a height of 10.9 km. The centripetal acceleration of the plane is 16.7 m/s2. What is the angular velocity of the plane moving in uniform circular motion? Take the radius of the earth to be 6400 km.
Please help, I've tried everything
I changed the height to angle by dividing the height by the radius
I then plugged that into the formula
wf^2 = wi^2 +2(acceleration)(angle)
but I'm not getting the right answer
3 answers
if r is the radius above earth center the speed is totally impossible. I suspect a typo
not sure about impossible...
this is around escape velocity
this is around escape velocity
0 answers