5^(3x−8)·5^(4x)=25^(2x)
this one also stumped me
3^(2x−1)= 1/(27^x)
3 answers
27 = 3^3, so
3^(2x−1)= 1/(27^x)
3^(2x−1)= 1/3^(3x)
3^(2x-1) = 3^(-3x)
2x-1 = -3x
5x = 1
x = 1/5
25=5^2, so
5^(3x−8)·5^(4x) = 25^(2x)
5^(3x−8)·5^(4x) = 5^(4x)
3x-8+4x = 4x
x = 8/3
3^(2x−1)= 1/(27^x)
3^(2x−1)= 1/3^(3x)
3^(2x-1) = 3^(-3x)
2x-1 = -3x
5x = 1
x = 1/5
25=5^2, so
5^(3x−8)·5^(4x) = 25^(2x)
5^(3x−8)·5^(4x) = 5^(4x)
3x-8+4x = 4x
x = 8/3
thanks you Steve!
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