150 children have to go on a school
tour. They can use minibuses, which
carry x pupils each, or cars which
carry y pupils each. The
mathematics teacher works out that
they could just manage with 10 minibuses and 6 cars, or with 5
minibuses and 18 cars. Write down
two equations and hence find the
value of x and y.
3 answers
pls help me i dont know what to do next
m minibuses
m x number in minis
n cars
n y = number in cars
10 minibuses means m = 10
10 x in buses
6 cars means n = 6
6 y in cars
so
10 x + 6 y = 150
but also
5x + 18 y = 150
now we have a plain old 2 eqn, 2 unknown problem
multiply the second equation by 2 and we have:
10 x + 6 y = 150
10 x + 36y = 300
----------------- subtract
-30 y = -150
so
y = 5
go back and get x now
10x+6(5) = 150
10 x = 120
x = 12
(12, 5)
m x number in minis
n cars
n y = number in cars
10 minibuses means m = 10
10 x in buses
6 cars means n = 6
6 y in cars
so
10 x + 6 y = 150
but also
5x + 18 y = 150
now we have a plain old 2 eqn, 2 unknown problem
multiply the second equation by 2 and we have:
10 x + 6 y = 150
10 x + 36y = 300
----------------- subtract
-30 y = -150
so
y = 5
go back and get x now
10x+6(5) = 150
10 x = 120
x = 12
(12, 5)
wow! Thank u somuch Damon. May God bless u
5 answers