Question

A Carnot engine of efficiency 41% operates with a cold reservoir at 24 °C and exhausts 1290 J of heat each cycle. What is the entropy change for the hot reservoir? Answer in J/K.

I keep getting the answer incorrect. Here is the work:
Efficiency = 100*(Th- Tc)/Th

41 = 100*(Th - (24+273))/Th

0.41 Th = Th - 297

Th = 297/(1-0.41)

= 503.4 K

entropy change = dQ/T = 1290/503.4

= 2.56 J/K

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