Asked by gorje
A prehistoric bone is found at an excavation site. If the bone originally contained 22 kg of carbon−14, how much would remain after 11,400 years?
Answers
Answered by
Damon
assuming 5730 year half life
a = Ai e^-kt
a/Ai = .5 = e^-k(5730)
ln .5 = -k(5730)
k = 1.21 *10^-4
so
a = 22 e^-(1.21*10^-4*11400)
= 22 * e^-1.38
= 22* .252
= 5.54 kg
a = Ai e^-kt
a/Ai = .5 = e^-k(5730)
ln .5 = -k(5730)
k = 1.21 *10^-4
so
a = 22 e^-(1.21*10^-4*11400)
= 22 * e^-1.38
= 22* .252
= 5.54 kg
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