Asked by Ana
A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.
b)How many revolutions does it make in 15 s if it starts at rest?
I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.
b)How many revolutions does it make in 15 s if it starts at rest?
I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.
Answers
Answered by
Scott
it accelerates for 4 s
... up to 8 rad/s
then spins for 11 s
... 88 rad
the ave vel during acceleration is
... ) + 8) / 2 = 4 rad/s
... spins 16 rad
104 rad total
... divide by 2π to find revolutions
... up to 8 rad/s
then spins for 11 s
... 88 rad
the ave vel during acceleration is
... ) + 8) / 2 = 4 rad/s
... spins 16 rad
104 rad total
... divide by 2π to find revolutions
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