Question

I need to find the pH of a 500 mL solution of pure water after adding 33.0 mg of H2SO4 and 18.0 mg of HCl. Please help! So far I have tried to find the moles of 33.0mg of H2SO4 and got 3.24. Then I calculated pH by multiplying the subscript of H (2) by the moles (3.24) and then took the negative log (-0.8). Do I do the same for HCl...and then what?