Asked by NORma
Tickets for a certain show cost
$15, $24,
or, for VIP seats,
$41.
If
ninenine
times as many
$15
tickets were sold as VIP tickets, and the number of
$15
tickets sold was
55
more than the sum of the number of
$24
tickets and VIP tickets, sales of all three kinds of tickets would total
$46 comma 46,152.
How many of each kind of ticket would have been sold?
$15, $24,
or, for VIP seats,
$41.
If
ninenine
times as many
$15
tickets were sold as VIP tickets, and the number of
$15
tickets sold was
55
more than the sum of the number of
$24
tickets and VIP tickets, sales of all three kinds of tickets would total
$46 comma 46,152.
How many of each kind of ticket would have been sold?
Answers
Answered by
Steve
If the number of seats for the categories is x,y,z then just list the data:
x = 9z
x = 55+y+z
15x+24y+41z = 46152
Now just solve for x,y,z
x = 9z
x = 55+y+z
15x+24y+41z = 46152
Now just solve for x,y,z
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