Asked by niki
Find an eqaution for the line passing through (1,3) and perpendicular to the line 3y=-2x+6
Answers
Answered by
bobpursley
y=-2/3 x +2
so line perpendicular will have slope of 1.5
y=1.5 x + b
3=1.5*1+b
b=1.5
y=1.5 x + 1.5
so line perpendicular will have slope of 1.5
y=1.5 x + b
3=1.5*1+b
b=1.5
y=1.5 x + 1.5
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