Asked by Asia Muhammad
Write an algebraic expression for y=tan (cos^-1 x/3)for 0<x<3.
Please Help!!
Please Help!!
Answers
Answered by
Reiny
look at the cos^-1 (x/3)
construct a triangle with base of x and hypotenuse of 3
by Pythagoras:
r^2 = x^2 + y^2
3^2 = x^2 + y^2
y^2 = 9 - x^2
y = √(9-x^2)
so we want the tangent
tan (cos^-1 x/3)
= opposite/adjacent
= √(9-x^2)/3
construct a triangle with base of x and hypotenuse of 3
by Pythagoras:
r^2 = x^2 + y^2
3^2 = x^2 + y^2
y^2 = 9 - x^2
y = √(9-x^2)
so we want the tangent
tan (cos^-1 x/3)
= opposite/adjacent
= √(9-x^2)/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.