Asked by Anonymous
Forces with magnitudes of 250 pounds and 130pounds act on an object at angles 45degrees and -60degrees respectively with the positive axis. Find the direction and magnitude of the resultant of these forces.
Answers
Answered by
Reiny
250 pounds at 45° ---> (250cos45, 250sin45)
130 pounds at -60° ---> (130cos(-60), 130sin(-60) )
Resultant = (250cos45, 250sin45)+(130cos(-60), 130sin(-60) )
= (125√2, 125√2) + (65 , -65√3)
= ( 125√2 + 65 , 125√2 - 65√3)
= appr (241.7767 , 64.1934)
maginitude = √(..^2 + ..^2) = 250.153
angle:
tanØ = 64.1934/241.7767
Ø = 14.87°
check my arithmetic
130 pounds at -60° ---> (130cos(-60), 130sin(-60) )
Resultant = (250cos45, 250sin45)+(130cos(-60), 130sin(-60) )
= (125√2, 125√2) + (65 , -65√3)
= ( 125√2 + 65 , 125√2 - 65√3)
= appr (241.7767 , 64.1934)
maginitude = √(..^2 + ..^2) = 250.153
angle:
tanØ = 64.1934/241.7767
Ø = 14.87°
check my arithmetic
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