Asked by Holly

A catapult of a spring constant 100N/M contains 2.0J of elastic potential energy when it is pulled back. What is the extension of the rubber band? I know that E= F/K but I don't know how to work out the force from the information provided, help would be much appreciated, thanks

Answers

Answered by Scott
e = 1/2 k x^2 ... (kind of like KE)

2.0 = 1/2 * 100 * x^2
Answered by jo
o.o4
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