Question
Find the local maximum and minimum values of the following curve within the given domain.
y=SECx-TANx 0 ≤ x ≤ 2π
y=SECx-TANx 0 ≤ x ≤ 2π
Answers
Steve
y = secx - tanx
y' = secx(tanx-secx)
y' = 0 when
secx=0 -- never
tanx-secx=0
secx(sinx-1) = 0
secx=0 -- never
sinx=1 -- x = pi/2
Now, we want x=pi/2 to be a solution, but unfortunately, neither secx nor tanx is defined there.
There are no min/max points on the graph of f(x), as seen at this url:
http://www.wolframalpha.com/input/?i=secx+-+tanx
y' = secx(tanx-secx)
y' = 0 when
secx=0 -- never
tanx-secx=0
secx(sinx-1) = 0
secx=0 -- never
sinx=1 -- x = pi/2
Now, we want x=pi/2 to be a solution, but unfortunately, neither secx nor tanx is defined there.
There are no min/max points on the graph of f(x), as seen at this url:
http://www.wolframalpha.com/input/?i=secx+-+tanx