Asked by matt
Find the local maximum and minimum values of the following curve within the given domain.
y=SECx-TANx 0 ≤ x ≤ 2π
y=SECx-TANx 0 ≤ x ≤ 2π
Answers
Answered by
Steve
y = secx - tanx
y' = secx(tanx-secx)
y' = 0 when
secx=0 -- never
tanx-secx=0
secx(sinx-1) = 0
secx=0 -- never
sinx=1 -- x = pi/2
Now, we want x=pi/2 to be a solution, but unfortunately, neither secx nor tanx is defined there.
There are no min/max points on the graph of f(x), as seen at this url:
http://www.wolframalpha.com/input/?i=secx+-+tanx
y' = secx(tanx-secx)
y' = 0 when
secx=0 -- never
tanx-secx=0
secx(sinx-1) = 0
secx=0 -- never
sinx=1 -- x = pi/2
Now, we want x=pi/2 to be a solution, but unfortunately, neither secx nor tanx is defined there.
There are no min/max points on the graph of f(x), as seen at this url:
http://www.wolframalpha.com/input/?i=secx+-+tanx
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.