Asked by Adam
d/dx integral e^t^2 dt from 1 to x^3
Please help. I think I'm supposed to use substitution for the x^3 and then apply the chain rule but I'm not sure how to do that.
Please help. I think I'm supposed to use substitution for the x^3 and then apply the chain rule but I'm not sure how to do that.
Answers
Answered by
Steve
The chain rule says that df/dx = df/du * du/dx. So, you have
e^(x^3)^2 (3x^2)
= 3x^2 e^(x^6)
now, technically, you have to subtract f(u) at the lower limit, but since d1/dx = 0, it just goes away.
wikipedia has a good article on this.
e^(x^3)^2 (3x^2)
= 3x^2 e^(x^6)
now, technically, you have to subtract f(u) at the lower limit, but since d1/dx = 0, it just goes away.
wikipedia has a good article on this.
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