Question

Suppose F(t) is an antiderivative of t^{3}. Then F'(t)= t^3.

According to the Second Fundamental Theorem of Calculus,
x
∫ (t^3)dt = ???
1

Answer using the function F

Answer 1

F' = f(x)dx/dx - f(1)d1/dx
= t^3 - 0
= t^3