Asked by James
Suppose F(t) is an antiderivative of t^{3}. Then F'(t)= t^3.
According to the Second Fundamental Theorem of Calculus,
x
∫ (t^3)dt = ???
1
Answer using the function F
According to the Second Fundamental Theorem of Calculus,
x
∫ (t^3)dt = ???
1
Answer using the function F
Answers
Answered by
Steve
F' = f(x)dx/dx - f(1)d1/dx
= t^3 - 0
= t^3
= t^3 - 0
= t^3
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