Asked by Jessica
A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the concentration of H2 was 0.400 M. Find the equilibrium concentrations of I2 and HI and then find the Keq at this temperature 2HI(g) <-> H2(g) + I2(g)
Answers
Answered by
DrBob222
M HI = mols/L = 4.00/2.00 = 2.00
.......2HI ==> H2 + I2
I ......2.......0....0
C.......-2x.....x....x
E.....2-2x......x....x
Substitute the E line into Keq expression. You know x = (H2) = 0.4,calculate concns and Keq from that.
.......2HI ==> H2 + I2
I ......2.......0....0
C.......-2x.....x....x
E.....2-2x......x....x
Substitute the E line into Keq expression. You know x = (H2) = 0.4,calculate concns and Keq from that.