Asked by frankie
A collection of thirty-seven coins consists of nickels, dimes and quarters. There are ten more dimes than nickels. Represent the value of all the coins using one variable.
Answers
Answered by
Reiny
number of nickels ---- x
number of dimes ----- x+10
number of quarters = 37-(x + x+10) = 27 - 2x
value of coins = 5x + 10(x+10) + 25(27-2x)
= 5x + 10x + 100 + 675 - 50x
= 775 - 35 x
number of dimes ----- x+10
number of quarters = 37-(x + x+10) = 27 - 2x
value of coins = 5x + 10(x+10) + 25(27-2x)
= 5x + 10x + 100 + 675 - 50x
= 775 - 35 x
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