Asked by samuel

(1) a car travelling at a constant speed of 20ms-1 overcomes a constant frictional resistance of 300N. What is the horse power of the engine? ( take 1h.p = 3/4 kw)
Answered by Scott
6000 Nm/s = 6 kw
Answered by Aja
M=f×s/t
Answered by Jumbotron
Recall;

Power = force x distance/time

also recall distance/time = velocity

also recall; Nm/s = Watts

Hence;

Power = 300N x 20m/s

Power = 6000Nm/s

Power = 6000watts or 6kw

Recall;

750watts = 1hp

but 1hp = 3/4kw

therefore;

750watts = 3/4kw

0.75kw 3/4kw

0.75kw = 3/4kw

6kw = xhp

Therefore;

xhp = 3/4 x 6/0.75

xhp = 4.5/0.75

xhp = 6hp
Answered by Jumbotron
Recall;

Power = force x distance/time

also recall distance/time = velocity

also recall; Nm/s = Watts

Hence;

Power = 300N x 20m/s

Power = 6000Nm/s

Power = 6000watts or 6kw

Recall;

750watts = 1hp

but 1hp = 3/4kw

therefore;

1hp = 0.75kw

xhp = 6kw

Therefore;

0.75 * xhp = 6* 1

xhp = 6/0.75

xhp = 8hp

Corrected
Answered by Victoria
It is correct
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