Question

The product of two consecutive positive integers is added to the larger of the two integers. Prove that the result is always a square number.

Thank you for your help.

Answer 1

think: (a+1)^2 = a^2+2a+1

Answer 2

n (n+1) + n+1
n^2 + n + n + 1

n^2 + 2n + 1
= (n+1)(n+1)

Answer 3

Thank you so much.

Answer 4

3+4 = 7
7+4 = 11
The square root of 11 not a whole number this is wrong😂😂😂