This is a limiting reagent (LR) problem and you know that because amounts are given for BOTH reactants.
CaCl2 + 2AgNO3 ==> Ca(NO3)2 + 2AgCl
mols CaCl2 = M x L = ? = approx 0.001 but you need to confirm.
mol AgNO3 = M x L = approx 0.001 x 1 = 0.001.
You see the mols AgCl are not the same; the correct value in LR problems is ALWAYS the smaller number. Therefore, 0.001 mol AgNO3 will be formed. g AgCl = mols AgCl x molar mass AgCl = ?
Determine the amount of a precipitate produced when 10mL of a 0.1M silver nitrate solution is mixed with 10mL of a 0.1M calcium chloride solution.
1 answer
1 answer