Asked by Anonymous
An astronaut lands on a distant planet and places a mathematical pendulum with a length of 50 cm. He measures that the pendulum makes 100 oscillations in 136 sec. What is the gravity acceleration on that planet.
Answers
Answered by
Henry
T = 136s/100cycles. = 1.36 s./cycle.
T^2 = 39.48*L/g = (1.36)^2.
L/g = 0.0468, g = 0.50/0.0468 = 10.7 m/s^2.
T^2 = 39.48*L/g = (1.36)^2.
L/g = 0.0468, g = 0.50/0.0468 = 10.7 m/s^2.
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