Asked by Tala

A student was experimentally checking the stoichiometry of a reaction. The student correctly predicted that the reaction should produce 1.82 g of al2(so4)3(s). When the student dried and weighed the al2(so4)3(s) produced, its mass was 1.94 g. The percent difference of the experiment was?
Answered by Ms. Sue
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Answered by DrBob222
The 1.82 is 100%. That is theoretical yield (TY).
The 1.94 is actual yield (AY)
% yield = (AY/TY)*100 = ?
You can take the difference.
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