with the information given, you should be able to form the equation
h = -16t^2 + 68t + 6
dh/dt = -32t + 68
= 0 for a max of h
32t = 68
t = 2.125
evaluate h when t = 2.125
Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 68 feet per second. How high will the ball go?
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