A solution of aqueous ammonia contains 28.0% NH3 by mass. the solution has a density of 0.898g/mL. calculate the volume of this solution required to make 425mLof 0.320M NH3 solution.

To calculate the volume of the solution required, we need to determine the amount of NH3 present in the solution.

Step 1: Calculate the mass of the 0.320M NH3 solution.
Mass = Volume × Density
Mass = 425 mL × 0.898 g/mL
Mass = 381.35 g

Step 2: Determine the amount of NH3 in the 381.35 g of solution.
Amount of NH3 = (Mass of NH3 / Total mass of solution) × 100
Amount of NH3 = (28.0 / 100) × 381.35 g
Amount of NH3 = 106.79 g

Step 3: Calculate the volume of the solution required to have 106.79 g of NH3.
Volume = (Amount of NH3 / Density)
Volume = 106.79 g / 0.898 g/mL
Volume ≈ 118.9 mL

Therefore, approximately 118.9 mL of the 28.0% NH3 solution is required to make a 425 mL 0.320M NH3 solution.