Asked by Ashlee

Solve.

x^2-xy+3y^2=15,
x-y=2

Thanks
Answered by Steve
just substitute: y = x-2, so

x^2 - x(x-2) + 3(x-2)^2 = 15
3x^2 - 10x - 3 = 0

solve for x, than y=x-2.
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