Asked by abigail
If 700 grams of glucose (C6H12O6) are fermented, what is the maximum volume in milliliters of ethanol (C2H5OH) that can form? (Density of ethanol is 0.79 g/mL)
Answers
Answered by
abigail
The fermentation of glucose to form ethanol occurs according to the following chemical
reaction:
C6H12O6(aq) → 2 C2H5OH(l) + 2 CO2(g)
reaction:
C6H12O6(aq) → 2 C2H5OH(l) + 2 CO2(g)
Answered by
DrBob222
C6H12O6(aq) → 2 C2H5OH(l) + 2 CO2(g)
mols glucose = grams/molar mass = ?
mols ethanol = 2x that (look at the coefficients in the balanced equation).
g ethanol = mols ethanol x molar mass ethanol.
Convert to mL. volume in mL = grams/density.
mols glucose = grams/molar mass = ?
mols ethanol = 2x that (look at the coefficients in the balanced equation).
g ethanol = mols ethanol x molar mass ethanol.
Convert to mL. volume in mL = grams/density.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.