Asked by Morgyn

The record time for a Tour de France cyclist to ascend the famed 1100-m-high Alpe d'Huez was 37.5 min, set by Marco Pantani in 1997. Pantani and his bike had a mass of 65 kg. Assume the body works with 25 % efficiency.
A)How many Calories did he expend during this climb?
B)What was his average metabolic power during the climb?

Answers

Answered by Damon
gain in potential = m g h
= 65 * 9.81 * 1100 Joules
eff = ..25
so
.25 energy = 65* 9.81 * 1100
so energy expended = 4*65*9.81*1100
Joules
4184 Joules = 1000 calories
so in Calories
(4/4.184)65*9.81*1100

power = energy expended/ time
in watts = 4*65*9.81*1100/(37.5*60)
Answered by Anonymous
no
Answered by Duck
Cuck
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