Asked by Morgyn
                The record time for a Tour de France cyclist to ascend the famed 1100-m-high Alpe d'Huez was 37.5 min, set by Marco Pantani in 1997. Pantani and his bike had a mass of 65 kg. Assume the body works with 25 % efficiency.
A)How many Calories did he expend during this climb?
B)What was his average metabolic power during the climb?
            
        A)How many Calories did he expend during this climb?
B)What was his average metabolic power during the climb?
Answers
                    Answered by
            Damon
            
    gain in potential = m g h 
= 65 * 9.81 * 1100 Joules
eff = ..25
so
.25 energy = 65* 9.81 * 1100
so energy expended = 4*65*9.81*1100
Joules
4184 Joules = 1000 calories
so in Calories
(4/4.184)65*9.81*1100
power = energy expended/ time
in watts = 4*65*9.81*1100/(37.5*60)
    
= 65 * 9.81 * 1100 Joules
eff = ..25
so
.25 energy = 65* 9.81 * 1100
so energy expended = 4*65*9.81*1100
Joules
4184 Joules = 1000 calories
so in Calories
(4/4.184)65*9.81*1100
power = energy expended/ time
in watts = 4*65*9.81*1100/(37.5*60)
                    Answered by
            Anonymous
            
    no
    
                    Answered by
            Duck
            
    Cuck
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.