Asked by Morgyn
The record time for a Tour de France cyclist to ascend the famed 1100-m-high Alpe d'Huez was 37.5 min, set by Marco Pantani in 1997. Pantani and his bike had a mass of 65 kg. Assume the body works with 25 % efficiency.
A)How many Calories did he expend during this climb?
B)What was his average metabolic power during the climb?
A)How many Calories did he expend during this climb?
B)What was his average metabolic power during the climb?
Answers
Answered by
Damon
gain in potential = m g h
= 65 * 9.81 * 1100 Joules
eff = ..25
so
.25 energy = 65* 9.81 * 1100
so energy expended = 4*65*9.81*1100
Joules
4184 Joules = 1000 calories
so in Calories
(4/4.184)65*9.81*1100
power = energy expended/ time
in watts = 4*65*9.81*1100/(37.5*60)
= 65 * 9.81 * 1100 Joules
eff = ..25
so
.25 energy = 65* 9.81 * 1100
so energy expended = 4*65*9.81*1100
Joules
4184 Joules = 1000 calories
so in Calories
(4/4.184)65*9.81*1100
power = energy expended/ time
in watts = 4*65*9.81*1100/(37.5*60)
Answered by
Anonymous
no
Answered by
Duck
Cuck
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