Asked by InfaRed
In triangle ABC, AB = 3, AC = 5, and BC = 4. The medians AD, BE, and CF of triangle ABC intersect at the centroid G. Let the projections of G onto BC, AC, and AB be P, Q, and R, respectively. Find GP + GQ + GR.
Answers
Answered by
Steve
since the centroid is 2/3 of the way from each vertex to the opposite side, the projections on the sides are 2/3 the length of the sides.
Their sum is thus 2/3 of the perimeter of ABC = 8
Their sum is thus 2/3 of the perimeter of ABC = 8
Answered by
InfaRed
8 isn't correct.
Answered by
Steve
You are correct. I calculated using 2/3 of the projection of the median, which is wrong.
I'll think on it some more. You do the same...
I'll think on it some more. You do the same...
Answered by
Steve
It's 16.
Answered by
InfaRed
16 is correct. Thanks!
Answered by
......
no it is not correct
Answered by
......
it is not 16
Answered by
......
the answer is 47/15
Answered by
wow cheaters
wow stop cheating on acumbulos
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