Find the values of c guaranteed by the mean value theorem for integrals.
f(x)= x^3
[0,3]
2 answers
Is 27/4 right?
You should know immediately that 27/4 is not correct, since it does not lie in the interval [0,3]!
You want c such that f'(c) = (f(3)-f(0))/(3-0)
3c^2 = 27/3
c = √3
You want c such that f'(c) = (f(3)-f(0))/(3-0)
3c^2 = 27/3
c = √3