Asked by Ian

Find the values of c guaranteed by the mean value theorem for integrals.

f(x)= x^3

[0,3]
Answered by Ian
Is 27/4 right?
Answered by Steve
You should know immediately that 27/4 is not correct, since it does not lie in the interval [0,3]!

You want c such that f'(c) = (f(3)-f(0))/(3-0)

3c^2 = 27/3
c = √3
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