Asked by Angie
An unknown metal has a mass of 4.67g. It is heated to 95.1 C and then placed in a calorimeter that contains 24.3g of water at 21.7 C. The metal and water both reach a final temperature of 24.6 C. What is the specific heat of this metal? What is the unknown metal?
Q=mcdeltaT
c=Q/(m)(delta T)
c= 95.1 C/(4.67g)(2.9C)= 7.0g
Q=mcdeltaT
c=Q/(m)(delta T)
c= 95.1 C/(4.67g)(2.9C)= 7.0g
Answers
Answered by
DrBob222
Your abswer if 7 g makes no sense since specific heat is measured in J/g*C (or KJ)or cal/g*C. I'm not sure the problem can be worked without knowing the calorimeter constant.
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