V^2 = Vo^2 + 2g*h = 0 + 19.6*2 = 39.2, V = 6.26 m/s.
PE = Mg*h = 0.98*1 = 0.98 J.
KE = 0.5M*V^2 = 0.05*39.2 = 1.96 J.
PE = Mg*h = 0.98*1 = 0.98 J.
KE = 0.5M*V^2 = 0.05*39.2 = 1.96 J.
When the body is at a height of 3m, it has potential energy due to its position in the Earth's gravitational field. The potential energy can be calculated using the formula:
Potential energy = mass x gravitational acceleration x height
So, P.E. = 0.1kg x 9.8 m/s^2 x 3m
But hold on a second! You're asking about when the body is 1m above the ground, not 3m. Oh, how gravity loves to throw us for a loop!
To find the potential energy at that point, let's calculate it using the new height of 1m:
P.E. = 0.1kg x 9.8 m/s^2 x 1m
Now, let's talk about kinetic energy. When the body is falling freely, it gains kinetic energy due to its motion. The formula for kinetic energy is:
Kinetic energy = 0.5 x mass x velocity^2
Now, the velocity of the body can be determined using the equation of motion:
velocity^2 = 2 x gravitational acceleration x height
Solving for velocity, we get:
velocity = sqrt(2 x gravitational acceleration x height)
So, the kinetic energy will be:
Kinetic energy = 0.5 x 0.1kg x (sqrt(2 x 9.8 m/s^2 x 1m))^2
And there you have it! The potential and kinetic energy of the body when it is 1m above the ground. Remember, gravity might make you fall, but humor will always lift your spirits!
Potential energy (PE) is given by the formula:
PE = mgh
where:
m = mass of the body (0.1kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height above the ground (1m)
Kinetic energy (KE) is given by the formula:
KE = (1/2)mv^2
where:
m = mass of the body (0.1kg)
v = velocity of the body
To find the velocity of the body when it is 1m above the ground, we can use the equation of motion:
v^2 = u^2 + 2gh
where:
u = initial velocity of the body (0 m/s, since it starts from rest)
Substituting the given values, we can solve for v:
v^2 = 0^2 + 2 * 9.8 * 1
v^2 = 19.6
v = √19.6
v ≈ 4.43 m/s
Now we can calculate the potential and kinetic energy:
PE = mgh = 0.1 * 9.8 * 1 = 0.98 J (Joules)
KE = (1/2)mv^2 = (1/2) * 0.1 * (4.43)^2 ≈ 0.98 J (Joules)
Therefore, when the body is 1m above the ground, its potential energy and kinetic energy are both approximately 0.98 Joules.
Potential Energy (PE) = mass (m) * gravity (g) * height (h)
Kinetic Energy (KE) = 1/2 * mass (m) * velocity squared (v^2)
Given that the mass (m) of the body is 0.1 kg, the height (h) is 1 m, and the acceleration due to gravity (g) is approximately 9.8 m/s^2, we can plug these values into the formulas.
First, let's calculate the potential energy (PE):
PE = m * g * h
= 0.1 kg * 9.8 m/s^2 * 1 m
= 0.98 Joules
Next, we can calculate the kinetic energy (KE). To find the velocity (v), we need to use the equation of motion:
v^2 = u^2 + 2 * a * s
Where:
u is the initial velocity (which is 0 m/s, as the body is starting to fall)
a is the acceleration due to gravity (g)
s is the distance traveled (which is the initial height (h) minus the final height (1 m))
s = h - 1
= 3 m - 1 m
= 2 m
Now, we can find the velocity:
v^2 = 0^2 + 2 * 9.8 m/s^2 * 2 m
= 39.2 m^2/s^2
Finally, we can calculate the kinetic energy (KE):
KE = 1/2 * m * v^2
= 1/2 * 0.1 kg * 39.2 m^2/s^2
= 1.96 Joules
Therefore, when the body is 1 meter above the ground, its potential energy (PE) is 0.98 Joules and its kinetic energy (KE) is 1.96 Joules.