Asked by Amit
A body of mass 0.1kg starts to fall freely under gravity from a height of 3m.Calculate its potential and kinetic energy when it is 1m above the groind
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h = 0 + 19.6*2 = 39.2, V = 6.26 m/s.
PE = Mg*h = 0.98*1 = 0.98 J.
KE = 0.5M*V^2 = 0.05*39.2 = 1.96 J.
PE = Mg*h = 0.98*1 = 0.98 J.
KE = 0.5M*V^2 = 0.05*39.2 = 1.96 J.
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