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Question

Find an equation of a hyperbola with vertices (0​,3) and ​(−4​,3) and e=3/2.

Thank you
8 years ago

Answers

Reiny
2a = 4
a = 2

e = c/a
c/2 = 3/2
c = 3

in a hyperbola:
a^2 + b^2 = c^2
4 + b^2 = 9
b^2 = 5
a^2 = 4
centre is (-2,3)

(x+2)^2 /4 - (y-3)^2 /5 = 1
8 years ago

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