Asked by Andrew
                How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 165 mL of coffee at 91.0°C so that the resulting combination will have a temperature of 62.1°C? Assume that coffee and water have the same density and the same specific heat (4.18 J/g·°C) across the temperature range.
            
            
        Answers
                    Answered by
            DrBob222
            
    heat gained by cold water + heat lost by hot coffee = 0
[mass cold H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass coffee x specific heat coffee x (Tfinal-Tinitial) = 0
Substitute and solve for mass cold H2O, then convert to mL.
mass = volume x density.
You know density and mass, solve for volume in mL.
    
[mass cold H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass coffee x specific heat coffee x (Tfinal-Tinitial) = 0
Substitute and solve for mass cold H2O, then convert to mL.
mass = volume x density.
You know density and mass, solve for volume in mL.
                    Answered by
            Anonymous
            
    55.6
    
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