Asked by Kaeo
The field is in a right triangle shape.The hypotenuse of this field is 6 metres and the peerimeter of this field is 14 metres.What is the area of the lawn?
Answers
Answered by
Damon
a^2 + b^2 = 36
a + b + 6 = 14 so a = 8-b
64 - 16 b + 2 b^2 =36
2 b^2 - 16 b + 28 = 0
b^2 - 8 b + 14 = 0
b = [ 8 +/- sqrt (64 -56) ]/2
b = [ 8 +/- 2sqrt 2 ]/2
b = 4+/-sqrt 2
if b = 4+sqrt 2
a = 4 - sqrt 2
A = (1/2)ab
= (1/2)(16-2) = 7 m^2
a + b + 6 = 14 so a = 8-b
64 - 16 b + 2 b^2 =36
2 b^2 - 16 b + 28 = 0
b^2 - 8 b + 14 = 0
b = [ 8 +/- sqrt (64 -56) ]/2
b = [ 8 +/- 2sqrt 2 ]/2
b = 4+/-sqrt 2
if b = 4+sqrt 2
a = 4 - sqrt 2
A = (1/2)ab
= (1/2)(16-2) = 7 m^2
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