A : B = 5:11 = 10 : 22 = ... = 10x : 22x
A : B : C = 2:3:15 = 10:15:75 = ... = 10x:15x:75x
in solution X we have 10x/(22x) of A
so amount of A in 400 L ofX is (10/22)(400) = appr 181.8 L
in solution Y amount of C in 400 L
= 75x/(100x)(400) = 300 L
Two chemicals,A and B are combined in the ratio 5:11 by volume to form another solution X. A second solution Y is formed by combining chemicals, A,B and C in the ratio 2:3:15 by volume.
Find the volume of chemical A in 400 litres of solution X and chemicals C in 400 litres of solution Y.
1 answer