Asked by Jyscah
Working together, a man and woman could complete a job in 6 days. A man workingcqlone could do it in 5 days less than a woman could. In how much time would each other do the job alone?
Answers
Answered by
Reiny
woman's rate ---- 1/x
man's rate ----- 1/(x-5) , where x > 5
combined rate = 1/x + 1/(x-5) = (x-5 +x)/(x(x-5))
= (2x-5)/(x^2 - 5x)
(2x-5)/(x^2 - 5x) = 1/6
x^2 - 5x = 12x - 30
x^2 - 17x + 30 = 0
(x-15)(x-2) = 0
x = 15 or x =2 , but x > 5
x = 15
The woman can do the job in 15 days, the man could do it in 10 days
man's rate ----- 1/(x-5) , where x > 5
combined rate = 1/x + 1/(x-5) = (x-5 +x)/(x(x-5))
= (2x-5)/(x^2 - 5x)
(2x-5)/(x^2 - 5x) = 1/6
x^2 - 5x = 12x - 30
x^2 - 17x + 30 = 0
(x-15)(x-2) = 0
x = 15 or x =2 , but x > 5
x = 15
The woman can do the job in 15 days, the man could do it in 10 days
There are no AI answers yet. The ability to request AI answers is coming soon!